What are the solutions to the equation (x+9)(x-3)=0 ?

The solutions to the equation (x+9)(x-3)=0 are x=-9,x=3

Find the zeros of (x+9)(x-3)=0

The zeros of (x+9)(x-3)=0 are x=-9,x=3

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(x + 9) (x - 3) = 0

x = - 9, x = 3

Solution steps

(x + 9) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 9 = 0 or x - 3 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 9, x = 3

a, 9 a^{2} - a^{2} = c^{2}

x (3 (x - 4)) + (x - 3) + (4 x + 2) + (2 x - 1) = 300

19.2 = - 0.3 x^{2} + 6 x

6.842 = (2 m + 0.4) \cdot (2 m + 0.7)

- 2 x^{2} - 8 x + 10 = 0

What are the solutions to the equation (x+9)(x-3)=0 ?
The solutions to the equation (x+9)(x-3)=0 are x=-9,x=3
Find the zeros of (x+9)(x-3)=0
The zeros of (x+9)(x-3)=0 are x=-9,x=3