What are the solutions to the equation 0=(x-2)(2x+3) ?

The solutions to the equation 0=(x-2)(2x+3) are x=2,x=-3/2

Find the zeros of 0=(x-2)(2x+3)

The zeros of 0=(x-2)(2x+3) are x=2,x=-3/2

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0 = (x - 2) (2 x + 3)

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

0 = (x - 2) (2 x + 3)

Switch sides

(x - 2) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

\frac{2}{3} x^{2} - \frac{3}{2} x = 0

2 x^{2} + 16.38 x + 33.01 x = 0

x^{2} = 6 x + 5

x, y^{9} x^{2} - 4 y^{2} = 36

x (x - 2) = 24

What are the solutions to the equation 0=(x-2)(2x+3) ?
The solutions to the equation 0=(x-2)(2x+3) are x=2,x=-3/2
Find the zeros of 0=(x-2)(2x+3)
The zeros of 0=(x-2)(2x+3) are x=2,x=-3/2