What are the solutions to the equation 2n^2-6n-36=0 ?

The solutions to the equation 2n^2-6n-36=0 are n=6,n=-3

Find the zeros of 2n^2-6n-36=0

The zeros of 2n^2-6n-36=0 are n=6,n=-3

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2 n^{2} - 6 n - 36 = 0

n = 6, n = - 3

Solution steps

2 n^{2} - 6 n - 36 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 ( - 36 )}{2 \cdot 2}

(- 6)^{2} - 4 \cdot 2 (- 36) = 18

n_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 2}, n_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 2}

n = \frac{- ( - 6 ) + 18}{2 \cdot 2} : 6

n = \frac{- ( - 6 ) - 18}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

n = 6, n = - 3

2 x^{2} + 12 x - 3 = 0

10 k^{2} + 9 k - 1 = 0

n^{2} = 5 n

x^{2} + 20 x - 60 = 0

w^{2} + 8 w - 48 = 0

What are the solutions to the equation 2n^2-6n-36=0 ?
The solutions to the equation 2n^2-6n-36=0 are n=6,n=-3
Find the zeros of 2n^2-6n-36=0
The zeros of 2n^2-6n-36=0 are n=6,n=-3