What are the solutions to the equation solvefor x,3x^2-3x+9=0 ?

The solutions to the equation solvefor x,3x^2-3x+9=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

Find the zeros of solvefor x,3x^2-3x+9=0

The zeros of solvefor x,3x^2-3x+9=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2

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x, 3 x^{2} - 3 x + 9 = 0

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

Solution steps

3 x^{2} - 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

(- 3)^{2} - 4 \cdot 3 \cdot 9 : 311 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3 11 i}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3 11 i}{2 \cdot 3} : \frac{1}{2} + i \frac{11}{2}

x = \frac{- ( - 3 ) - 3 11 i}{2 \cdot 3} : \frac{1}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{11}{2}, x = \frac{1}{2} - i \frac{11}{2}

x, f (x + 3) = 4 x^{2} + 4 x - 2

0 = - 16 t^{2} + 7744

r^{2} + 4 r + 196 = 0

(x + 3) (2 x - 1) = (2 x - 1) (3 x - 5)

1 x^{2} + 6400 x - 115200000 = 0

What are the solutions to the equation solvefor x,3x^2-3x+9=0 ?
The solutions to the equation solvefor x,3x^2-3x+9=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2
Find the zeros of solvefor x,3x^2-3x+9=0
The zeros of solvefor x,3x^2-3x+9=0 are x= 1/2+i(sqrt(11))/2 ,x= 1/2-i(sqrt(11))/2