What are the solutions to the equation solvefor x,y^2-x^2=k^2 ?

The solutions to the equation solvefor x,y^2-x^2=k^2 are x=sqrt(-k^2+y^2),x=-sqrt(-k^2+y^2)

Find the zeros of solvefor x,y^2-x^2=k^2

The zeros of solvefor x,y^2-x^2=k^2 are x=sqrt(-k^2+y^2),x=-sqrt(-k^2+y^2)

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solve for

x, y^{2} - x^{2} = k^{2}

x = - k^{2} + y^{2}, x = - - k^{2} + y^{2}

Solution steps

y^{2} - x^{2} = k^{2}

Move

y^{2}

to the right side

- x^{2} = k^{2} - y^{2}

Divide both sides by

- 1

x^{2} = - k^{2} + y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - k^{2} + y^{2}, x = - - k^{2} + y^{2}

w, r^{2} + w^{2} = 0

0.05 = - 0.00008 x^{2} - 0.0035 x + 1.0519

(2 x + 9)^{2} - (x - 1)^{2} = 4 (x - 3)^{2} + 40 x - 3

x^{2} - 20 x - 21 = 0

- 3 x^{2} + 35 x - 22 - (- 4 x^{2} + 3 x - 71) = 0

What are the solutions to the equation solvefor x,y^2-x^2=k^2 ?
The solutions to the equation solvefor x,y^2-x^2=k^2 are x=sqrt(-k^2+y^2),x=-sqrt(-k^2+y^2)
Find the zeros of solvefor x,y^2-x^2=k^2
The zeros of solvefor x,y^2-x^2=k^2 are x=sqrt(-k^2+y^2),x=-sqrt(-k^2+y^2)