What are the solutions to the equation (y-2)^2=1 ?

The solutions to the equation (y-2)^2=1 are y=3,y=1

Find the zeros of (y-2)^2=1

The zeros of (y-2)^2=1 are y=3,y=1

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(y - 2)^{2} = 1

y = 3, y = 1

Solution steps

(y - 2)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 2 = 1 : y = 3

Solve

y - 2 = - 1 : y = 1

The solutions to the quadratic equation are:

y = 3, y = 1

x^{2} - 36 = 0

x^{2} - 5 x - 250 = 0

0.02844 x^{2} - 0.1596 x + 0.218 = 0

c^{2} = 5^{2} + 1 1^{2}

- 4 x^{2} + 11 x + 3 = 0

What are the solutions to the equation (y-2)^2=1 ?
The solutions to the equation (y-2)^2=1 are y=3,y=1
Find the zeros of (y-2)^2=1
The zeros of (y-2)^2=1 are y=3,y=1