What are the solutions to the equation 7x^2+4x+15=0 ?

The solutions to the equation 7x^2+4x+15=0 are x=-2/7+i(sqrt(101))/7 ,x=-2/7-i(sqrt(101))/7

Find the zeros of 7x^2+4x+15=0

The zeros of 7x^2+4x+15=0 are x=-2/7+i(sqrt(101))/7 ,x=-2/7-i(sqrt(101))/7

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7 x^{2} + 4 x + 15 = 0

x = - \frac{2}{7} + i \frac{101}{7}, x = - \frac{2}{7} - i \frac{101}{7}

Solution steps

7 x^{2} + 4 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 7 \cdot 15}{2 \cdot 7}

Simplify

4^{2} - 4 \cdot 7 \cdot 15 : 2101 i

x_{1, 2} = \frac{- 4 \pm 2 101 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 4 + 2 101 i}{2 \cdot 7}, x_{2} = \frac{- 4 - 2 101 i}{2 \cdot 7}

x = \frac{- 4 + 2 101 i}{2 \cdot 7} : - \frac{2}{7} + i \frac{101}{7}

x = \frac{- 4 - 2 101 i}{2 \cdot 7} : - \frac{2}{7} - i \frac{101}{7}

The solutions to the quadratic equation are:

x = - \frac{2}{7} + i \frac{101}{7}, x = - \frac{2}{7} - i \frac{101}{7}

4 z^{2} - b z - 1 = 0

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x^{2} - 5 x + 0 = 0

x (x + 3) = 2 (7 - x) + 10

640 = - 490 t^{2} + 1120 t

What are the solutions to the equation 7x^2+4x+15=0 ?
The solutions to the equation 7x^2+4x+15=0 are x=-2/7+i(sqrt(101))/7 ,x=-2/7-i(sqrt(101))/7
Find the zeros of 7x^2+4x+15=0
The zeros of 7x^2+4x+15=0 are x=-2/7+i(sqrt(101))/7 ,x=-2/7-i(sqrt(101))/7