What are the solutions to the equation x^2-300x+18900=0 ?

The solutions to the equation x^2-300x+18900=0 are x=210,x=90

Find the zeros of x^2-300x+18900=0

The zeros of x^2-300x+18900=0 are x=210,x=90

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x^{2} - 300 x + 18900 = 0

x = 210, x = 90

Solution steps

x^{2} - 300 x + 18900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot 18900}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot 18900 = 120

x_{1, 2} = \frac{- ( - 300 ) \pm 120}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 300 ) + 120}{2 \cdot 1}, x_{2} = \frac{- ( - 300 ) - 120}{2 \cdot 1}

x = \frac{- ( - 300 ) + 120}{2 \cdot 1} : 210

x = \frac{- ( - 300 ) - 120}{2 \cdot 1} : 90

The solutions to the quadratic equation are:

x = 210, x = 90

x^{2} - 3 x - 5 = 0

1.5 = \frac{1}{2} \cdot 9.8 \cdot x^{2}

x^{2} + 1 + 1 = 0

4 x^{2} + 12 x + 37

7. 3^{2} + b^{2} = 1 3^{2}

What are the solutions to the equation x^2-300x+18900=0 ?
The solutions to the equation x^2-300x+18900=0 are x=210,x=90
Find the zeros of x^2-300x+18900=0
The zeros of x^2-300x+18900=0 are x=210,x=90