What are the solutions to the equation 0=40x-4.9x^2 ?

The solutions to the equation 0=40x-4.9x^2 are x=0,x= 400/49

Find the zeros of 0=40x-4.9x^2

The zeros of 0=40x-4.9x^2 are x=0,x= 400/49

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0 = 40 x - 4.9 x^{2}

x = 0, x = \frac{400}{49}

Decimal Notation

x = 0, x = 8.16326 \dots

Solution steps

0 = 40 x - 4.9 x^{2}

Multiply both sides by

10

0 = 400 x - 49 x^{2}

Switch sides

400 x - 49 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 49 x^{2} + 400 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 49 ) \cdot 0}{2 ( - 49 )}

40 0^{2} - 4 (- 49) \cdot 0 = 400

x_{1, 2} = \frac{- 400 \pm 400}{2 ( - 49 )}

Separate the solutions

x_{1} = \frac{- 400 + 400}{2 ( - 49 )}, x_{2} = \frac{- 400 - 400}{2 ( - 49 )}

x = \frac{- 400 + 400}{2 ( - 49 )} : 0

x = \frac{- 400 - 400}{2 ( - 49 )} : \frac{400}{49}

The solutions to the quadratic equation are:

x = 0, x = \frac{400}{49}

m^{2} = 5 m - 6

x^{2} + (2 x)^{2} = 1

x^{2} + (2 x)^{2} = 5

5 w^{2} - 8 w - 7 = 0

2 mn x^{2} + n x - 2 m x - 1 = 0

What are the solutions to the equation 0=40x-4.9x^2 ?
The solutions to the equation 0=40x-4.9x^2 are x=0,x= 400/49
Find the zeros of 0=40x-4.9x^2
The zeros of 0=40x-4.9x^2 are x=0,x= 400/49