What are the solutions to the equation quadraticformula x^2+6x-2=0 ?

The solutions to the equation quadraticformula x^2+6x-2=0 are x=-3+sqrt(11),x=-3-sqrt(11)

Find the zeros of quadraticformula x^2+6x-2=0

The zeros of quadraticformula x^2+6x-2=0 are x=-3+sqrt(11),x=-3-sqrt(11)

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x^{2} + 6 x - 2 = 0

x = - 3 + 11, x = - 3 - 11

Decimal Notation

x = 0.31662 \dots, x = - 6.31662 \dots

Solution steps

x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 2) = 211

x_{1, 2} = \frac{- 6 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 11}{2 \cdot 1}

x = \frac{- 6 + 2 11}{2 \cdot 1} : - 3 + 11

x = \frac{- 6 - 2 11}{2 \cdot 1} : - 3 - 11

The solutions to the quadratic equation are:

x = - 3 + 11, x = - 3 - 11

x, x^{2} + 4 x y - 4 y^{2} - 3 x + 4 y - 10 = 0

\frac{0.011 \cdot 2000 \cdot x ^{2}}{2 \cdot 9.81 \cdot 0.16} = 35

x^{2} + 3 = 67

(x - 5) (x + 5) = (2 x + 3) (x - 2)

x^{2} + 28 x - 16 = 0

What are the solutions to the equation quadraticformula x^2+6x-2=0 ?
The solutions to the equation quadraticformula x^2+6x-2=0 are x=-3+sqrt(11),x=-3-sqrt(11)
Find the zeros of quadraticformula x^2+6x-2=0
The zeros of quadraticformula x^2+6x-2=0 are x=-3+sqrt(11),x=-3-sqrt(11)