What are the solutions to the equation x^2+0.8x=0.09 ?

The solutions to the equation x^2+0.8x=0.09 are x= 1/10 ,x=-9/10

Find the zeros of x^2+0.8x=0.09

The zeros of x^2+0.8x=0.09 are x= 1/10 ,x=-9/10

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x^{2} + 0.8 x = 0.09

x = \frac{1}{10}, x = - \frac{9}{10}

Decimal Notation

x = 0.1, x = - 0.9

Solution steps

x^{2} + 0.8 x = 0.09

Multiply both sides by

100

100 x^{2} + 80 x = 9

Move

9

to the left side

100 x^{2} + 80 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 100 ( - 9 )}{2 \cdot 100}

8 0^{2} - 4 \cdot 100 (- 9) = 100

x_{1, 2} = \frac{- 80 \pm 100}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 80 + 100}{2 \cdot 100}, x_{2} = \frac{- 80 - 100}{2 \cdot 100}

x = \frac{- 80 + 100}{2 \cdot 100} : \frac{1}{10}

x = \frac{- 80 - 100}{2 \cdot 100} : - \frac{9}{10}

The solutions to the quadratic equation are:

x = \frac{1}{10}, x = - \frac{9}{10}

x, P (3 x - 1) = x^{2} - 5 x + 1

(x - 1)^{2} = 3 x + 1

(x - 1) (x + 3) = 5 (x + 2) - 3

v^{2} + 9 v + 8 = 0

(x + 3)^{2} = 49

What are the solutions to the equation x^2+0.8x=0.09 ?
The solutions to the equation x^2+0.8x=0.09 are x= 1/10 ,x=-9/10
Find the zeros of x^2+0.8x=0.09
The zeros of x^2+0.8x=0.09 are x= 1/10 ,x=-9/10