What are the solutions to the equation 2(x-7)^2=22 ?

The solutions to the equation 2(x-7)^2=22 are x=sqrt(11)+7,x=-sqrt(11)+7

Find the zeros of 2(x-7)^2=22

The zeros of 2(x-7)^2=22 are x=sqrt(11)+7,x=-sqrt(11)+7

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2 (x - 7)^{2} = 22

x = 11 + 7, x = - 11 + 7

Decimal Notation

x = 10.31662 \dots, x = 3.68337 \dots

Solution steps

2 (x - 7)^{2} = 22

Divide both sides by

2

(x - 7)^{2} = 11

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 7 = 11 : x = 11 + 7

Solve

x - 7 = - 11 : x = - 11 + 7

The solutions to the quadratic equation are:

x = 11 + 7, x = - 11 + 7

(x - 2) (x + 5) = 30

n^{2} = 56 + n

h^{2} = 10 0^{2} + 10 0^{2}

8 - x^{2} = 4 x + 12

5 x^{2} + 7 x^{2} - 25 5^{2} = 0

What are the solutions to the equation 2(x-7)^2=22 ?
The solutions to the equation 2(x-7)^2=22 are x=sqrt(11)+7,x=-sqrt(11)+7
Find the zeros of 2(x-7)^2=22
The zeros of 2(x-7)^2=22 are x=sqrt(11)+7,x=-sqrt(11)+7