What are the solutions to the equation 2x^2-x-60=0 ?

The solutions to the equation 2x^2-x-60=0 are x=(1+sqrt(481))/4 ,x=(1-sqrt(481))/4

Find the zeros of 2x^2-x-60=0

The zeros of 2x^2-x-60=0 are x=(1+sqrt(481))/4 ,x=(1-sqrt(481))/4

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2 x^{2} - x - 60 = 0

x = \frac{1 + 481}{4}, x = \frac{1 - 481}{4}

Decimal Notation

x = 5.73292 \dots, x = - 5.23292 \dots

Solution steps

2 x^{2} - x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 60) = 481

x_{1, 2} = \frac{- ( - 1 ) \pm 481}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 481}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 481}{2 \cdot 2}

x = \frac{- ( - 1 ) + 481}{2 \cdot 2} : \frac{1 + 481}{4}

x = \frac{- ( - 1 ) - 481}{2 \cdot 2} : \frac{1 - 481}{4}

The solutions to the quadratic equation are:

x = \frac{1 + 481}{4}, x = \frac{1 - 481}{4}

y, y^{2} = \frac{x ^{3}}{2 - x}

x, (x + 3)^{2} + (y + 1)^{2} = r^{2}

4 x^{2} - 12 x = - 9

3 t (2 t - 1) = 4 t + 3

v^{2} = - 13 v

What are the solutions to the equation 2x^2-x-60=0 ?
The solutions to the equation 2x^2-x-60=0 are x=(1+sqrt(481))/4 ,x=(1-sqrt(481))/4
Find the zeros of 2x^2-x-60=0
The zeros of 2x^2-x-60=0 are x=(1+sqrt(481))/4 ,x=(1-sqrt(481))/4