What are the solutions to the equation -3x^2+12x-5=0 ?

The solutions to the equation -3x^2+12x-5=0 are x=(6-sqrt(21))/3 ,x=(6+sqrt(21))/3

Find the zeros of -3x^2+12x-5=0

The zeros of -3x^2+12x-5=0 are x=(6-sqrt(21))/3 ,x=(6+sqrt(21))/3

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- 3 x^{2} + 12 x - 5 = 0

x = \frac{6 - 21}{3}, x = \frac{6 + 21}{3}

Decimal Notation

x = 0.47247 \dots, x = 3.52752 \dots

Solution steps

- 3 x^{2} + 12 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 5 )}{2 ( - 3 )}

1 2^{2} - 4 (- 3) (- 5) = 221

x_{1, 2} = \frac{- 12 \pm 2 21}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 21}{2 ( - 3 )}, x_{2} = \frac{- 12 - 2 21}{2 ( - 3 )}

x = \frac{- 12 + 2 21}{2 ( - 3 )} : \frac{6 - 21}{3}

x = \frac{- 12 - 2 21}{2 ( - 3 )} : \frac{6 + 21}{3}

The solutions to the quadratic equation are:

x = \frac{6 - 21}{3}, x = \frac{6 + 21}{3}

2 x^{2} - 10 x + 8

2 x^{2} - 10 x + 3

x^{2} + (- \frac{1}{6})^{2} = 1^{2}

(X + 2) (X - 3) + 2 (3 X - 4) = 3 X + 1

x^{2} + (\frac{90}{2000}) x + (\frac{1500}{2000}) = 0

What are the solutions to the equation -3x^2+12x-5=0 ?
The solutions to the equation -3x^2+12x-5=0 are x=(6-sqrt(21))/3 ,x=(6+sqrt(21))/3
Find the zeros of -3x^2+12x-5=0
The zeros of -3x^2+12x-5=0 are x=(6-sqrt(21))/3 ,x=(6+sqrt(21))/3