What are the solutions to the equation -5x^2+x+1=0 ?

The solutions to the equation -5x^2+x+1=0 are x=-(-1+sqrt(21))/(10),x=(1+sqrt(21))/(10)

Find the zeros of -5x^2+x+1=0

The zeros of -5x^2+x+1=0 are x=-(-1+sqrt(21))/(10),x=(1+sqrt(21))/(10)

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- 5 x^{2} + x + 1 = 0

x = - \frac{- 1 + 21}{10}, x = \frac{1 + 21}{10}

Decimal Notation

x = - 0.35825 \dots, x = 0.55825 \dots

Solution steps

- 5 x^{2} + x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 5 ) \cdot 1}{2 ( - 5 )}

1^{2} - 4 (- 5) \cdot 1 = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 ( - 5 )}, x_{2} = \frac{- 1 - 21}{2 ( - 5 )}

x = \frac{- 1 + 21}{2 ( - 5 )} : - \frac{- 1 + 21}{10}

x = \frac{- 1 - 21}{2 ( - 5 )} : \frac{1 + 21}{10}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 21}{10}, x = \frac{1 + 21}{10}

0.12 \cdot 1 0^{- 5} x^{2} + 0.026 x + 100 = 0

(x + \frac{b}{3})^{2} - 2 - \frac{b ^{2}}{9} = 0

2 x^{2} - x - 2

(2 x + 3)^{2} = 4

x^{2} + 4 x + 4 = 2 x + 7

What are the solutions to the equation -5x^2+x+1=0 ?
The solutions to the equation -5x^2+x+1=0 are x=-(-1+sqrt(21))/(10),x=(1+sqrt(21))/(10)
Find the zeros of -5x^2+x+1=0
The zeros of -5x^2+x+1=0 are x=-(-1+sqrt(21))/(10),x=(1+sqrt(21))/(10)