What are the solutions to the equation x^2+2^2=0 ?

The solutions to the equation x^2+2^2=0 are x=2i,x=-2i

Find the zeros of x^2+2^2=0

The zeros of x^2+2^2=0 are x=2i,x=-2i

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x^{2} + 2^{2} = 0

x = 2 i, x = - 2 i

Solution steps

x^{2} + 2^{2} = 0

Move

2^{2}

to the right side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

3 q^{2} - 18 q + 24 = 0

0 = 1 - 0^{2} - z^{2}

5 x^{2} - 7 x = - 4 + 3 x^{2}

- 11 a^{2} + 32 a + 256 = 0

- 7 x^{2} - 21 x - 5

What are the solutions to the equation x^2+2^2=0 ?
The solutions to the equation x^2+2^2=0 are x=2i,x=-2i
Find the zeros of x^2+2^2=0
The zeros of x^2+2^2=0 are x=2i,x=-2i