What are the solutions to the equation 0=7+k^2+8k ?

The solutions to the equation 0=7+k^2+8k are k=-1,k=-7

Find the zeros of 0=7+k^2+8k

The zeros of 0=7+k^2+8k are k=-1,k=-7

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0 = 7 + k^{2} + 8 k

k = - 1, k = - 7

Solution steps

0 = 7 + k^{2} + 8 k

Switch sides

7 + k^{2} + 8 k = 0

Write in the standard form

a x^{2} + b x + c = 0

k^{2} + 8 k + 7 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

k_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 8 + 6}{2 \cdot 1}, k_{2} = \frac{- 8 - 6}{2 \cdot 1}

k = \frac{- 8 + 6}{2 \cdot 1} : - 1

k = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = - 1, k = - 7

(r^{2} - 4) = 0

x^{2} - 3 x = x + 5

x^{2} + 4 x - 64 = 0

x^{2} - 6 x + 5 = 2 x - 7

2 x (x + 1) + x (x - 2) = 3 x + 18

What are the solutions to the equation 0=7+k^2+8k ?
The solutions to the equation 0=7+k^2+8k are k=-1,k=-7
Find the zeros of 0=7+k^2+8k
The zeros of 0=7+k^2+8k are k=-1,k=-7