What are the solutions to the equation 0=-4.9(t-0.5)^2+7 ?

The solutions to the equation 0=-4.9(t-0.5)^2+7 are t=1.69522…,t=-0.69522…

Find the zeros of 0=-4.9(t-0.5)^2+7

The zeros of 0=-4.9(t-0.5)^2+7 are t=1.69522…,t=-0.69522…

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0 = - 4.9 (t - 0.5)^{2} + 7

t = 1.69522 \dots, t = - 0.69522 \dots

Solution steps

0 = - 4.9 (t - 0.5)^{2} + 7

Switch sides

- 4.9 (t - 0.5)^{2} + 7 = 0

Move

7

to the right side

- 4.9 (t - 0.5)^{2} = - 7

Multiply both sides by

10

- 49 (t - 0.5)^{2} = - 70

Divide both sides by

- 49

(t - 0.5)^{2} = \frac{10}{7}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t - 0.5 = \frac{10}{7} : t = 1.69522 \dots

Solve

t - 0.5 = - \frac{10}{7} : t = - 0.69522 \dots

The solutions to the quadratic equation are:

t = 1.69522 \dots, t = - 0.69522 \dots

m^{1} = m^{2}

x, 18 x^{2} y + 4 y^{3} - 2 = 0

- 2 x^{2} + 4 x + 9 = - 3

(x - 3)^{2} - 5 (x - 3) + 4 = 0

2 x^{2} - 16 x + 24 = 0

What are the solutions to the equation 0=-4.9(t-0.5)^2+7 ?
The solutions to the equation 0=-4.9(t-0.5)^2+7 are t=1.69522…,t=-0.69522…
Find the zeros of 0=-4.9(t-0.5)^2+7
The zeros of 0=-4.9(t-0.5)^2+7 are t=1.69522…,t=-0.69522…