What are the solutions to the equation x^2-2x+3=0 ?

The solutions to the equation x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

Find the zeros of x^2-2x+3=0

The zeros of x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i

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x^{2} - 2 x + 3 = 0

x = 1 + 2 i, x = 1 - 2 i

Solution steps

x^{2} - 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2 i}{2 \cdot 1} : 1 + 2 i

x = \frac{- ( - 2 ) - 2 2 i}{2 \cdot 1} : 1 - 2 i

The solutions to the quadratic equation are:

x = 1 + 2 i, x = 1 - 2 i

\frac{28}{- 7}

8 m + 7 - 2 m < 13

2 x^{2} - 13 x y + 20 y^{2}

3 x - 7 = 8

\frac{∣ x + 2 ∣}{∣ 2 x - 3 ∣} < 1

What are the solutions to the equation x^2-2x+3=0 ?
The solutions to the equation x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i
Find the zeros of x^2-2x+3=0
The zeros of x^2-2x+3=0 are x=1+sqrt(2)i,x=1-sqrt(2)i