What are the solutions to the equation -4x^2+2x-5=0 ?

The solutions to the equation -4x^2+2x-5=0 are x= 1/4-i(sqrt(19))/4 ,x= 1/4+i(sqrt(19))/4

Find the zeros of -4x^2+2x-5=0

The zeros of -4x^2+2x-5=0 are x= 1/4-i(sqrt(19))/4 ,x= 1/4+i(sqrt(19))/4

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- 4 x^{2} + 2 x - 5 = 0

x = \frac{1}{4} - i \frac{19}{4}, x = \frac{1}{4} + i \frac{19}{4}

Solution steps

- 4 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 4 ) ( - 5 )}{2 ( - 4 )}

Simplify

2^{2} - 4 (- 4) (- 5) : 219 i

x_{1, 2} = \frac{- 2 \pm 2 19 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 19 i}{2 ( - 4 )}, x_{2} = \frac{- 2 - 2 19 i}{2 ( - 4 )}

x = \frac{- 2 + 2 19 i}{2 ( - 4 )} : \frac{1}{4} - i \frac{19}{4}

x = \frac{- 2 - 2 19 i}{2 ( - 4 )} : \frac{1}{4} + i \frac{19}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} - i \frac{19}{4}, x = \frac{1}{4} + i \frac{19}{4}

6 x^{2} + 6 x = 1

(x - 5)^{2} - 2 = 79

x, 0 = 1.35 x^{2} - 11.74 x + 8.62

- 400 (x)^{2} + 9600 x + 792000 = 0

x^{2} - 12 + 4 x = 0

What are the solutions to the equation -4x^2+2x-5=0 ?
The solutions to the equation -4x^2+2x-5=0 are x= 1/4-i(sqrt(19))/4 ,x= 1/4+i(sqrt(19))/4
Find the zeros of -4x^2+2x-5=0
The zeros of -4x^2+2x-5=0 are x= 1/4-i(sqrt(19))/4 ,x= 1/4+i(sqrt(19))/4