What are the solutions to the equation y(y+5)=750 ?

The solutions to the equation y(y+5)=750 are y=25,y=-30

Find the zeros of y(y+5)=750

The zeros of y(y+5)=750 are y=25,y=-30

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y (y + 5) = 750

y = 25, y = - 30

Solution steps

y (y + 5) = 750

Expand

y (y + 5) : y^{2} + 5 y

y^{2} + 5 y = 750

Move

750

to the left side

y^{2} + 5 y - 750 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 750 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 750) = 55

y_{1, 2} = \frac{- 5 \pm 55}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 55}{2 \cdot 1}, y_{2} = \frac{- 5 - 55}{2 \cdot 1}

y = \frac{- 5 + 55}{2 \cdot 1} : 25

y = \frac{- 5 - 55}{2 \cdot 1} : - 30

The solutions to the quadratic equation are:

y = 25, y = - 30

4 x^{2} + 16 x + 13 = 0

x^{2} - 20 x + 33 = 0

4 x^{2} - 20 = 5

4 y^{2} - 7 y - 4 = 0

117 = 0.0443213 (x)^{2}

What are the solutions to the equation y(y+5)=750 ?
The solutions to the equation y(y+5)=750 are y=25,y=-30
Find the zeros of y(y+5)=750
The zeros of y(y+5)=750 are y=25,y=-30