What are the solutions to the equation h^2=1^2+1^2 ?

The solutions to the equation h^2=1^2+1^2 are h=sqrt(2),h=-sqrt(2)

Find the zeros of h^2=1^2+1^2

The zeros of h^2=1^2+1^2 are h=sqrt(2),h=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

h^{2} = 1^{2} + 1^{2}

h = 2, h = - 2

Decimal Notation

h = 1.41421 \dots, h = - 1.41421 \dots

Solution steps

h^{2} = 1^{2} + 1^{2}

Simplify

1^{2} + 1^{2} : 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

h = 2, h = - 2

x, (x y + 3)^{2} + (x + y)^{2} = 8

\frac{1}{5} x^{2} = 4

x, 3 e^{4 y + 8} = 6 x^{2} - 2

- 5 x^{2} + 3 x + 14 = 0

u^{2} - 8 u + 7 = 0

What are the solutions to the equation h^2=1^2+1^2 ?
The solutions to the equation h^2=1^2+1^2 are h=sqrt(2),h=-sqrt(2)
Find the zeros of h^2=1^2+1^2
The zeros of h^2=1^2+1^2 are h=sqrt(2),h=-sqrt(2)