What are the solutions to the equation 0=x^2+5x+1 ?

The solutions to the equation 0=x^2+5x+1 are x=(-5+sqrt(21))/2 ,x=(-5-sqrt(21))/2

Find the zeros of 0=x^2+5x+1

The zeros of 0=x^2+5x+1 are x=(-5+sqrt(21))/2 ,x=(-5-sqrt(21))/2

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0 = x^{2} + 5 x + 1

x = \frac{- 5 + 21}{2}, x = \frac{- 5 - 21}{2}

Decimal Notation

x = - 0.20871 \dots, x = - 4.79128 \dots

Solution steps

0 = x^{2} + 5 x + 1

Switch sides

x^{2} + 5 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 1 = 21

x_{1, 2} = \frac{- 5 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 21}{2 \cdot 1}, x_{2} = \frac{- 5 - 21}{2 \cdot 1}

x = \frac{- 5 + 21}{2 \cdot 1} : \frac{- 5 + 21}{2}

x = \frac{- 5 - 21}{2 \cdot 1} : \frac{- 5 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 21}{2}, x = \frac{- 5 - 21}{2}

(117 - x) (333 - x) - 8 1^{2} = 0

x, (2 x - 1)^{2} = 9 (y^{2} + z^{2})

b, z = - \frac{b ^{2} x}{y}

- 8 x^{2} + 10 x = 0

x^{2} - 10 x - 67 = 8

What are the solutions to the equation 0=x^2+5x+1 ?
The solutions to the equation 0=x^2+5x+1 are x=(-5+sqrt(21))/2 ,x=(-5-sqrt(21))/2
Find the zeros of 0=x^2+5x+1
The zeros of 0=x^2+5x+1 are x=(-5+sqrt(21))/2 ,x=(-5-sqrt(21))/2