What are the solutions to the equation -2x^2-9x-5=0 ?

The solutions to the equation -2x^2-9x-5=0 are x=-(9+sqrt(41))/4 ,x=-(9-sqrt(41))/4

Find the zeros of -2x^2-9x-5=0

The zeros of -2x^2-9x-5=0 are x=-(9+sqrt(41))/4 ,x=-(9-sqrt(41))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 x^{2} - 9 x - 5 = 0

x = - \frac{9 + 41}{4}, x = - \frac{9 - 41}{4}

Decimal

x = - 3.85078 \dots, x = - 0.64921 \dots

Solution steps

- 2 x^{2} - 9 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

(- 9)^{2} - 4 (- 2) (- 5) = 41

x_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 41}{2 ( - 2 )}, x_{2} = \frac{- ( - 9 ) - 41}{2 ( - 2 )}

x = \frac{- ( - 9 ) + 41}{2 ( - 2 )} : - \frac{9 + 41}{4}

x = \frac{- ( - 9 ) - 41}{2 ( - 2 )} : - \frac{9 - 41}{4}

The solutions to the quadratic equation are:

x = - \frac{9 + 41}{4}, x = - \frac{9 - 41}{4}

x, h^{2} = x^{2} + 2 y^{2}

4 x^{2} + a^{2} = 4 a x + b^{2}

x^{2} - 10 x - 66 = 0

x^{2} + 5 x - 2 = 0

3 y^{2} + y - 2 = 0

What are the solutions to the equation -2x^2-9x-5=0 ?
The solutions to the equation -2x^2-9x-5=0 are x=-(9+sqrt(41))/4 ,x=-(9-sqrt(41))/4
Find the zeros of -2x^2-9x-5=0
The zeros of -2x^2-9x-5=0 are x=-(9+sqrt(41))/4 ,x=-(9-sqrt(41))/4