What are the solutions to the equation 3s^2-9s-1=0 ?

The solutions to the equation 3s^2-9s-1=0 are s=(9+sqrt(93))/6 ,s=(9-sqrt(93))/6

Find the zeros of 3s^2-9s-1=0

The zeros of 3s^2-9s-1=0 are s=(9+sqrt(93))/6 ,s=(9-sqrt(93))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 s^{2} - 9 s - 1 = 0

s = \frac{9 + 93}{6}, s = \frac{9 - 93}{6}

Decimal Notation

s = 3.10727 \dots, s = - 0.10727 \dots

Solution steps

3 s^{2} - 9 s - 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 (- 1) = 93

s_{1, 2} = \frac{- ( - 9 ) \pm 93}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- ( - 9 ) + 93}{2 \cdot 3}, s_{2} = \frac{- ( - 9 ) - 93}{2 \cdot 3}

s = \frac{- ( - 9 ) + 93}{2 \cdot 3} : \frac{9 + 93}{6}

s = \frac{- ( - 9 ) - 93}{2 \cdot 3} : \frac{9 - 93}{6}

The solutions to the quadratic equation are:

s = \frac{9 + 93}{6}, s = \frac{9 - 93}{6}

2 x^{2} = - 7 x - 6

h^{2} - 10 h - 4 = 0

w^{2} + 12 w

x^{2} - 30 = 7 x

x (x + 3) = 5 x + 3

What are the solutions to the equation 3s^2-9s-1=0 ?
The solutions to the equation 3s^2-9s-1=0 are s=(9+sqrt(93))/6 ,s=(9-sqrt(93))/6
Find the zeros of 3s^2-9s-1=0
The zeros of 3s^2-9s-1=0 are s=(9+sqrt(93))/6 ,s=(9-sqrt(93))/6