What are the solutions to the equation 11^2+6^2=c^2 ?

The solutions to the equation 11^2+6^2=c^2 are c=sqrt(157),c=-sqrt(157)

Find the zeros of 11^2+6^2=c^2

The zeros of 11^2+6^2=c^2 are c=sqrt(157),c=-sqrt(157)

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1 1^{2} + 6^{2} = c^{2}

c = 157, c = - 157

Decimal

c = 12.52996 \dots, c = - 12.52996 \dots

Solution steps

1 1^{2} + 6^{2} = c^{2}

Switch sides

c^{2} = 1 1^{2} + 6^{2}

Simplify

1 1^{2} + 6^{2} : 157

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 157, c = - 157

\frac{3 x ^{2}}{8} = 0

a^{2} x^{2} - 1 = 0

6 x^{2} - 6 n = 11

m^{2} + 40 \cdot m + \frac{1}{16 \cdot 1 0 ^{- 4}} = 0

\frac{2}{3} x^{2} - 256 x + 12 8^{2} = 0

What are the solutions to the equation 11^2+6^2=c^2 ?
The solutions to the equation 11^2+6^2=c^2 are c=sqrt(157),c=-sqrt(157)
Find the zeros of 11^2+6^2=c^2
The zeros of 11^2+6^2=c^2 are c=sqrt(157),c=-sqrt(157)