What are the solutions to the equation solvefor y,y^2=x(3-x)^2 ?

The solutions to the equation solvefor y,y^2=x(3-x)^2 are y=(3-x)sqrt(x),y=-(3-x)sqrt(x)

Find the zeros of solvefor y,y^2=x(3-x)^2

The zeros of solvefor y,y^2=x(3-x)^2 are y=(3-x)sqrt(x),y=-(3-x)sqrt(x)

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solve for

y, y^{2} = x (3 - x)^{2}

y = (3 - x) x, y = - (3 - x) x

Solution steps

y^{2} = x (3 - x)^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x (3 - x)^{2}, y = - x (3 - x)^{2}

Simplify

x (3 - x)^{2} : (3 - x) x

Simplify

- x (3 - x)^{2} : - (3 - x) x

y = (3 - x) x, y = - (3 - x) x

- 5 (x - 3) + 2 = \frac{1}{2} x (x - 2)

x^{2} - 2 x + 1 = x + 1

3 x^{2} - 5 x = - 1

x^{2} + 9 x + 17 = 0

x, x^{2} + y^{2} - 2 x - 6 y + f = 0

What are the solutions to the equation solvefor y,y^2=x(3-x)^2 ?
The solutions to the equation solvefor y,y^2=x(3-x)^2 are y=(3-x)sqrt(x),y=-(3-x)sqrt(x)
Find the zeros of solvefor y,y^2=x(3-x)^2
The zeros of solvefor y,y^2=x(3-x)^2 are y=(3-x)sqrt(x),y=-(3-x)sqrt(x)