What are the solutions to the equation 4x^2+8x-45=0 ?

The solutions to the equation 4x^2+8x-45=0 are x= 5/2 ,x=-9/2

Find the zeros of 4x^2+8x-45=0

The zeros of 4x^2+8x-45=0 are x= 5/2 ,x=-9/2

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4 x^{2} + 8 x - 45 = 0

x = \frac{5}{2}, x = - \frac{9}{2}

Decimal Notation

x = 2.5, x = - 4.5

Solution steps

4 x^{2} + 8 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 ( - 45 )}{2 \cdot 4}

8^{2} - 4 \cdot 4 (- 45) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 4}, x_{2} = \frac{- 8 - 28}{2 \cdot 4}

x = \frac{- 8 + 28}{2 \cdot 4} : \frac{5}{2}

x = \frac{- 8 - 28}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{9}{2}

12 x^{2} - 12

x^{2} = 0.34

- 50 x + 600 = 250

2 x^{2} + 18 x - 20

What are the solutions to the equation 4x^2+8x-45=0 ?
The solutions to the equation 4x^2+8x-45=0 are x= 5/2 ,x=-9/2
Find the zeros of 4x^2+8x-45=0
The zeros of 4x^2+8x-45=0 are x= 5/2 ,x=-9/2