What are the solutions to the equation 0.05x^2+2x+100=0 ?

The solutions to the equation 0.05x^2+2x+100=0 are x=-20+40i,x=-20-40i

Find the zeros of 0.05x^2+2x+100=0

The zeros of 0.05x^2+2x+100=0 are x=-20+40i,x=-20-40i

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0.05 x^{2} + 2 x + 100 = 0

x = - 20 + 40 i, x = - 20 - 40 i

Solution steps

0.05 x^{2} + 2 x + 100 = 0

Multiply both sides by

100

5 x^{2} + 200 x + 10000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 200 \pm 20 0 ^{2} - 4 \cdot 5 \cdot 10000}{2 \cdot 5}

Simplify

20 0^{2} - 4 \cdot 5 \cdot 10000 : 400 i

x_{1, 2} = \frac{- 200 \pm 400 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 200 + 400 i}{2 \cdot 5}, x_{2} = \frac{- 200 - 400 i}{2 \cdot 5}

x = \frac{- 200 + 400 i}{2 \cdot 5} : - 20 + 40 i

x = \frac{- 200 - 400 i}{2 \cdot 5} : - 20 - 40 i

The solutions to the quadratic equation are:

x = - 20 + 40 i, x = - 20 - 40 i

(x^{2} - 81) = 0

2 (3 x + 5) + 2 (x - 5) = 2 (3 x + 5) (x - 5)

x^{2} + 9 x + 15 = 0

2 5^{2} - 7^{2} = x^{2}

X^{2} - 5 X + 4 = 0

What are the solutions to the equation 0.05x^2+2x+100=0 ?
The solutions to the equation 0.05x^2+2x+100=0 are x=-20+40i,x=-20-40i
Find the zeros of 0.05x^2+2x+100=0
The zeros of 0.05x^2+2x+100=0 are x=-20+40i,x=-20-40i