What are the solutions to the equation 6x^2+2x-2=0 ?

The solutions to the equation 6x^2+2x-2=0 are x=(-1+sqrt(13))/6 ,x=-(1+sqrt(13))/6

Find the zeros of 6x^2+2x-2=0

The zeros of 6x^2+2x-2=0 are x=(-1+sqrt(13))/6 ,x=-(1+sqrt(13))/6

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6 x^{2} + 2 x - 2 = 0

x = \frac{- 1 + 13}{6}, x = - \frac{1 + 13}{6}

Decimal Notation

x = 0.43425 \dots, x = - 0.76759 \dots

Solution steps

6 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 2) = 213

x_{1, 2} = \frac{- 2 \pm 2 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 13}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 13}{2 \cdot 6}

x = \frac{- 2 + 2 13}{2 \cdot 6} : \frac{- 1 + 13}{6}

x = \frac{- 2 - 2 13}{2 \cdot 6} : - \frac{1 + 13}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 13}{6}, x = - \frac{1 + 13}{6}

z, ln (x^{2} + y^{2}) + 3^{x y} + z^{2} + z = 0

x^{2} + x = 240

x^{2} + 45 x - 2430 = 0

10 \cdot 50 = \frac{1}{2} \cdot x^{2} + 10 \cdot 30

5 x^{2} + 11 x - 36 = 0

What are the solutions to the equation 6x^2+2x-2=0 ?
The solutions to the equation 6x^2+2x-2=0 are x=(-1+sqrt(13))/6 ,x=-(1+sqrt(13))/6
Find the zeros of 6x^2+2x-2=0
The zeros of 6x^2+2x-2=0 are x=(-1+sqrt(13))/6 ,x=-(1+sqrt(13))/6