What are the solutions to the equation 4(c+7)4(c+7)=36 ?

The solutions to the equation 4(c+7)4(c+7)=36 are c=-11/2 ,c=-17/2

Find the zeros of 4(c+7)4(c+7)=36

The zeros of 4(c+7)4(c+7)=36 are c=-11/2 ,c=-17/2

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4 (c + 7) 4 (c + 7) = 36

c = - \frac{11}{2}, c = - \frac{17}{2}

Decimal

c = - 5.5, c = - 8.5

Solution steps

4 (c + 7) \cdot 4 (c + 7) = 36

Simplify

16 (c + 7)^{2} = 36

Divide both sides by

16

\frac{16 ( c + 7 ) ^{2}}{16} = \frac{36}{16}

(c + 7)^{2} = \frac{9}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

c + 7 = \frac{9}{4} : c = - \frac{11}{2}

Solve

c + 7 = - \frac{9}{4} : c = - \frac{17}{2}

The solutions to the quadratic equation are:

c = - \frac{11}{2}, c = - \frac{17}{2}

8 x^{2} = - 7 n + 8

p, (y - x) (x p - y)^{2} = x^{3}

0 = x^{2} + 9 x + 7

2 x^{2} - 4 x - 6 = 0

2 x^{2} - \frac{3 x}{2} + \frac{1}{4} = 0

What are the solutions to the equation 4(c+7)4(c+7)=36 ?
The solutions to the equation 4(c+7)4(c+7)=36 are c=-11/2 ,c=-17/2
Find the zeros of 4(c+7)4(c+7)=36
The zeros of 4(c+7)4(c+7)=36 are c=-11/2 ,c=-17/2