What are the solutions to the equation (a-2)(a-4)=0 ?

The solutions to the equation (a-2)(a-4)=0 are a=2,a=4

Find the zeros of (a-2)(a-4)=0

The zeros of (a-2)(a-4)=0 are a=2,a=4

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(a - 2) (a - 4) = 0

a = 2, a = 4

Solution steps

(a - 2) (a - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 2 = 0 or a - 4 = 0

Solve

a - 2 = 0 : a = 2

Solve

a - 4 = 0 : a = 4

The solutions to the quadratic equation are:

a = 2, a = 4

11.13 X^{2} + 18.116 X - 16 = 0

x, f (x + 2) = x^{2}

a^{2} x^{2} - \frac{11}{6} a x - \frac{215}{144} = \frac{121}{144}

2 4^{2} = 2 5^{2} - b^{2}

12 x^{2} - 12 x - 144 = 0

What are the solutions to the equation (a-2)(a-4)=0 ?
The solutions to the equation (a-2)(a-4)=0 are a=2,a=4
Find the zeros of (a-2)(a-4)=0
The zeros of (a-2)(a-4)=0 are a=2,a=4