What are the solutions to the equation 3x^2+4x=9 ?

The solutions to the equation 3x^2+4x=9 are x=(-2+sqrt(31))/3 ,x=-(2+sqrt(31))/3

Find the zeros of 3x^2+4x=9

The zeros of 3x^2+4x=9 are x=(-2+sqrt(31))/3 ,x=-(2+sqrt(31))/3

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3 x^{2} + 4 x = 9

x = \frac{- 2 + 31}{3}, x = - \frac{2 + 31}{3}

Decimal Notation

x = 1.18925 \dots, x = - 2.52258 \dots

Solution steps

3 x^{2} + 4 x = 9

Move

9

to the left side

3 x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

4^{2} - 4 \cdot 3 (- 9) = 231

x_{1, 2} = \frac{- 4 \pm 2 31}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 4 + 2 31}{2 \cdot 3}, x_{2} = \frac{- 4 - 2 31}{2 \cdot 3}

x = \frac{- 4 + 2 31}{2 \cdot 3} : \frac{- 2 + 31}{3}

x = \frac{- 4 - 2 31}{2 \cdot 3} : - \frac{2 + 31}{3}

The solutions to the quadratic equation are:

x = \frac{- 2 + 31}{3}, x = - \frac{2 + 31}{3}

x^{2} + 18 x - 63 = 0

x^{2} + 5 = - 12

- y^{2} - 3 y

36 x^{2} = 1

(3 x + 5)^{2} = 10

What are the solutions to the equation 3x^2+4x=9 ?
The solutions to the equation 3x^2+4x=9 are x=(-2+sqrt(31))/3 ,x=-(2+sqrt(31))/3
Find the zeros of 3x^2+4x=9
The zeros of 3x^2+4x=9 are x=(-2+sqrt(31))/3 ,x=-(2+sqrt(31))/3