What are the solutions to the equation (3x+4)(2x-3)=0 ?

The solutions to the equation (3x+4)(2x-3)=0 are x=-4/3 ,x= 3/2

Find the zeros of (3x+4)(2x-3)=0

The zeros of (3x+4)(2x-3)=0 are x=-4/3 ,x= 3/2

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(3 x + 4) (2 x - 3) = 0

x = - \frac{4}{3}, x = \frac{3}{2}

Decimal Notation

x = - 1.33333 \dots, x = 1.5

Solution steps

(3 x + 4) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 4 = 0 or 2 x - 3 = 0

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{4}{3}, x = \frac{3}{2}

14 a c d - 7 c d + 21 c^{2} d^{2}

8 x^{2} - 14 x + 3 = 0

10 x - x^{2} - 16 = 0

\frac{d - 5}{3} = 5 - \frac{3 d}{2}

24 3^{\frac{5}{6}} \cdot 3^{\frac{5}{6}}

What are the solutions to the equation (3x+4)(2x-3)=0 ?
The solutions to the equation (3x+4)(2x-3)=0 are x=-4/3 ,x= 3/2
Find the zeros of (3x+4)(2x-3)=0
The zeros of (3x+4)(2x-3)=0 are x=-4/3 ,x= 3/2