What are the solutions to the equation a^2+8a-9=0 ?

The solutions to the equation a^2+8a-9=0 are a=1,a=-9

Find the zeros of a^2+8a-9=0

The zeros of a^2+8a-9=0 are a=1,a=-9

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a^{2} + 8 a - 9 = 0

a = 1, a = - 9

Solution steps

a^{2} + 8 a - 9 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

a_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 8 + 10}{2 \cdot 1}, a_{2} = \frac{- 8 - 10}{2 \cdot 1}

a = \frac{- 8 + 10}{2 \cdot 1} : 1

a = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

a = 1, a = - 9

4 n^{2} + 32 n + 64 = 0

5 x^{2} - 3 x - x = 0

\frac{x ^{2} - x + 5}{4} = 0

- 63 = - 2 y^{2} + 9

x, 16 x^{2} - 24 x y + 9 y^{2} - 60 x - 80 y + 100 = 0

What are the solutions to the equation a^2+8a-9=0 ?
The solutions to the equation a^2+8a-9=0 are a=1,a=-9
Find the zeros of a^2+8a-9=0
The zeros of a^2+8a-9=0 are a=1,a=-9