What are the solutions to the equation 3y^2+8y=2y+9 ?

The solutions to the equation 3y^2+8y=2y+9 are y=1,y=-3

Find the zeros of 3y^2+8y=2y+9

The zeros of 3y^2+8y=2y+9 are y=1,y=-3

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3 y^{2} + 8 y = 2 y + 9

y = 1, y = - 3

Solution steps

3 y^{2} + 8 y = 2 y + 9

Move

9

to the left side

3 y^{2} + 8 y - 9 = 2 y

Move

2 y

to the left side

3 y^{2} + 6 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 9) = 12

y_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- 6 + 12}{2 \cdot 3}, y_{2} = \frac{- 6 - 12}{2 \cdot 3}

y = \frac{- 6 + 12}{2 \cdot 3} : 1

y = \frac{- 6 - 12}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

y = 1, y = - 3

9 x^{2} - 48 = 0

5 y^{2} - 13 y + 6 = 0

n^{2} - n = 84

n^{2} - n = 56

X^{2} + 6 X + 9 = 0

What are the solutions to the equation 3y^2+8y=2y+9 ?
The solutions to the equation 3y^2+8y=2y+9 are y=1,y=-3
Find the zeros of 3y^2+8y=2y+9
The zeros of 3y^2+8y=2y+9 are y=1,y=-3