What are the solutions to the equation 16x^2-235x+151=0 ?

The solutions to the equation 16x^2-235x+151=0 are x=(235+sqrt(45561))/(32),x=(235-sqrt(45561))/(32)

Find the zeros of 16x^2-235x+151=0

The zeros of 16x^2-235x+151=0 are x=(235+sqrt(45561))/(32),x=(235-sqrt(45561))/(32)

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16 x^{2} - 235 x + 151 = 0

x = \frac{235 + 45561}{32}, x = \frac{235 - 45561}{32}

Decimal

x = 14.01406 \dots, x = 0.67343 \dots

Solution steps

16 x^{2} - 235 x + 151 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 235 ) \pm ( - 235 ) ^{2} - 4 \cdot 16 \cdot 151}{2 \cdot 16}

(- 235)^{2} - 4 \cdot 16 \cdot 151 = 45561

x_{1, 2} = \frac{- ( - 235 ) \pm 45561}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 235 ) + 45561}{2 \cdot 16}, x_{2} = \frac{- ( - 235 ) - 45561}{2 \cdot 16}

x = \frac{- ( - 235 ) + 45561}{2 \cdot 16} : \frac{235 + 45561}{32}

x = \frac{- ( - 235 ) - 45561}{2 \cdot 16} : \frac{235 - 45561}{32}

The solutions to the quadratic equation are:

x = \frac{235 + 45561}{32}, x = \frac{235 - 45561}{32}

3 x^{2} + 1 = - 13 x - 3

[\frac{7 x ( x )}{2 + ( - 7 )}] = 21

x^{2} - 10 x = - 5

x^{2} - 10 x = - 8

- \frac{49}{5} x = 7 (x + 7) (x - 2)

What are the solutions to the equation 16x^2-235x+151=0 ?
The solutions to the equation 16x^2-235x+151=0 are x=(235+sqrt(45561))/(32),x=(235-sqrt(45561))/(32)
Find the zeros of 16x^2-235x+151=0
The zeros of 16x^2-235x+151=0 are x=(235+sqrt(45561))/(32),x=(235-sqrt(45561))/(32)