What are the solutions to the equation 0.2q^2+4q-60=0 ?

The solutions to the equation 0.2q^2+4q-60=0 are q=10,q=-30

Find the zeros of 0.2q^2+4q-60=0

The zeros of 0.2q^2+4q-60=0 are q=10,q=-30

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0.2 q^{2} + 4 q - 60 = 0

q = 10, q = - 30

Solution steps

0.2 q^{2} + 4 q - 60 = 0

Multiply both sides by

10

2 q^{2} + 40 q - 600 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 2 ( - 600 )}{2 \cdot 2}

4 0^{2} - 4 \cdot 2 (- 600) = 80

q_{1, 2} = \frac{- 40 \pm 80}{2 \cdot 2}

Separate the solutions

q_{1} = \frac{- 40 + 80}{2 \cdot 2}, q_{2} = \frac{- 40 - 80}{2 \cdot 2}

q = \frac{- 40 + 80}{2 \cdot 2} : 10

q = \frac{- 40 - 80}{2 \cdot 2} : - 30

The solutions to the quadratic equation are:

q = 10, q = - 30

0.35 x^{2} - x + 0.35 = 0

6 x^{2} - 12 x = 720

1.034 s^{2} + 2.67 s + 2 = 0

3 y^{2} - y + 1 = 0

(a x^{2} - 5 x + 1) + (b x - 16 x^{2} - 9) = (- 14 x^{2} - 10 x + c)

What are the solutions to the equation 0.2q^2+4q-60=0 ?
The solutions to the equation 0.2q^2+4q-60=0 are q=10,q=-30
Find the zeros of 0.2q^2+4q-60=0
The zeros of 0.2q^2+4q-60=0 are q=10,q=-30