What are the solutions to the equation k^2+2k+3=0 ?

The solutions to the equation k^2+2k+3=0 are k=-1+sqrt(2)i,k=-1-sqrt(2)i

Find the zeros of k^2+2k+3=0

The zeros of k^2+2k+3=0 are k=-1+sqrt(2)i,k=-1-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} + 2 k + 3 = 0

k = - 1 + 2 i, k = - 1 - 2 i

Solution steps

k^{2} + 2 k + 3 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

k_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, k_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

k = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

k = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

k = - 1 + 2 i, k = - 1 - 2 i

1 0^{2} + 1 3^{2} = x^{2}

x, p^{2} x^{2} + (p^{2} - q^{2}) x - q^{2} = 0

25 = 7 + 35 t - 16 t^{2}

14 x^{2} + 17 x - 6 = 0

- 4 x^{2} - 8 x = - 32

What are the solutions to the equation k^2+2k+3=0 ?
The solutions to the equation k^2+2k+3=0 are k=-1+sqrt(2)i,k=-1-sqrt(2)i
Find the zeros of k^2+2k+3=0
The zeros of k^2+2k+3=0 are k=-1+sqrt(2)i,k=-1-sqrt(2)i