What are the solutions to the equation 7x^2-2x-4=0 ?

The solutions to the equation 7x^2-2x-4=0 are x=(1+sqrt(29))/7 ,x=(1-sqrt(29))/7

Find the zeros of 7x^2-2x-4=0

The zeros of 7x^2-2x-4=0 are x=(1+sqrt(29))/7 ,x=(1-sqrt(29))/7

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7 x^{2} - 2 x - 4 = 0

x = \frac{1 + 29}{7}, x = \frac{1 - 29}{7}

Decimal Notation

x = 0.91216 \dots, x = - 0.62645 \dots

Solution steps

7 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

(- 2)^{2} - 4 \cdot 7 (- 4) = 229

x_{1, 2} = \frac{- ( - 2 ) \pm 2 29}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 29}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 29}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 29}{2 \cdot 7} : \frac{1 + 29}{7}

x = \frac{- ( - 2 ) - 2 29}{2 \cdot 7} : \frac{1 - 29}{7}

The solutions to the quadratic equation are:

x = \frac{1 + 29}{7}, x = \frac{1 - 29}{7}

p (5 p - 3) = 0

3 x^{2} = 75

(250 + 10 x) (70 - 2 x) = 17980

\frac{x - 4}{5} = \frac{x - 2}{3} + 5

x, g = f

What are the solutions to the equation 7x^2-2x-4=0 ?
The solutions to the equation 7x^2-2x-4=0 are x=(1+sqrt(29))/7 ,x=(1-sqrt(29))/7
Find the zeros of 7x^2-2x-4=0
The zeros of 7x^2-2x-4=0 are x=(1+sqrt(29))/7 ,x=(1-sqrt(29))/7