What is the answer to 2(1-x)+2=-x+1/2 (2-x)+(x+4)/2 ?

The answer to 2(1-x)+2=-x+1/2 (2-x)+(x+4)/2 is x=1

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2(1-x)+2=-x+1/2 (2-x)+(x+4)/2

2 (1 - x) + 2 = - x + \frac{1}{2} (2 - x) + \frac{x + 4}{2}

x = 1

Solution steps

2 (1 - x) + 2 = - x + \frac{1}{2} (2 - x) + \frac{x + 4}{2}

Move

2

to the right side

2 (1 - x) = - x + 1

Expand

2 (1 - x) : 2 - 2 x

2 - 2 x = - x + 1

Move

2

to the right side

- 2 x = - x - 1

Move

x

to the left side

- x = - 1

Divide both sides by

- 1

x = 1

\frac{1}{6} x + 2 x - 1 = \frac{1}{3} (x + 9)

221 + 120 = (b mod 7)

\frac{11}{8} - \frac{5 q + 1}{12} = \frac{2 - q}{4} + \frac{11}{6}

z, 5 w + 9 z = 2 z + 3 w

\frac{1}{2} + \frac{3}{4} - x = - 3

What is the answer to 2(1-x)+2=-x+1/2 (2-x)+(x+4)/2 ?
The answer to 2(1-x)+2=-x+1/2 (2-x)+(x+4)/2 is x=1
Solve for x: 2(1-x)+2=-x+1/2 (2-x)+(x+4)/2
The solution is x=1