What is the answer to (4x-1)(5x+4)-20x^2=18 ?

The answer to (4x-1)(5x+4)-20x^2=18 is x=2

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(4x-1)(5x+4)-20x^2=18

(4 x - 1) (5 x + 4) - 20 x^{2} = 18

x = 2

Solution steps

(4 x - 1) (5 x + 4) - 20 x^{2} = 18

Expand

(4 x - 1) (5 x + 4) - 20 x^{2} : 11 x - 4

11 x - 4 = 18

Move

4

to the right side

11 x = 22

Divide both sides by

11

x = 2

0.9 a + 4.96 = 3.6 + 1.4 a

- 2 x = - 24

\frac{n + 4}{2} - 3 = 13

z = - 6 + i^{335} + 8 i^{87} + - 121

\frac{8}{3} t + \frac{1}{6} = \frac{2}{3}

What is the answer to (4x-1)(5x+4)-20x^2=18 ?
The answer to (4x-1)(5x+4)-20x^2=18 is x=2
Solve for x: (4x-1)(5x+4)-20x^2=18
The solution is x=2