What is the answer to (2x-1)(3-x)+2x^2=11 ?

The answer to (2x-1)(3-x)+2x^2=11 is x=2

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(2x-1)(3-x)+2x^2=11

(2 x - 1) (3 - x) + 2 x^{2} = 11

x = 2

Solution steps

(2 x - 1) (3 - x) + 2 x^{2} = 11

Expand

(2 x - 1) (3 - x) + 2 x^{2} : 7 x - 3

7 x - 3 = 11

Move

3

to the right side

7 x = 14

Divide both sides by

7

x = 2

2 x = - 4 (\frac{1}{4} - \frac{3}{4} x) + 4

5 (3 x - 2 x + 1) - 4 (3 x - 2) = 6 x + 2 (3 x - 2 x + 3)

I = \frac{n \cdot 1 0 ^{- 3}}{4 \cdot π \cdot ( n ^{2} )} \cdot 1 0^{6}

x, - 3 x - 2 y + 6 = 0

4 a + 7 = 23

What is the answer to (2x-1)(3-x)+2x^2=11 ?
The answer to (2x-1)(3-x)+2x^2=11 is x=2
Solve for x: (2x-1)(3-x)+2x^2=11
The solution is x=2