What is the answer to (2x+1)(x-4)+13=2x^2-10x ?

The answer to (2x+1)(x-4)+13=2x^2-10x is x=-3

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(2x+1)(x-4)+13=2x^2-10x

(2 x + 1) (x - 4) + 13 = 2 x^{2} - 10 x

x = - 3

Solution steps

(2 x + 1) (x - 4) + 13 = 2 x^{2} - 10 x

Expand

(2 x + 1) (x - 4) + 13 : 2 x^{2} - 7 x + 9

2 x^{2} - 7 x + 9 = 2 x^{2} - 10 x

Move

9

to the right side

2 x^{2} - 7 x = 2 x^{2} - 10 x - 9

Subtract

2 x^{2} - 10 x

from both sides

2 x^{2} - 7 x - (2 x^{2} - 10 x) = 2 x^{2} - 10 x - 9 - (2 x^{2} - 10 x)

Simplify

3 x = - 9

Divide both sides by

3

x = - 3

x, g = \frac{1}{2} f

a x - a d = b d - b x

x + \frac{5}{6} x + \frac{1}{10} \cdot \frac{5}{6} x = 230

(\frac{x}{\frac{1}{5}}) - 0.012 = 0.113

3 x + x - 9 = 2 x + 3

What is the answer to (2x+1)(x-4)+13=2x^2-10x ?
The answer to (2x+1)(x-4)+13=2x^2-10x is x=-3
Solve for x: (2x+1)(x-4)+13=2x^2-10x
The solution is x=-3