What are the solutions to the equation 5x^2-4x-6=0 ?

The solutions to the equation 5x^2-4x-6=0 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5

Find the zeros of 5x^2-4x-6=0

The zeros of 5x^2-4x-6=0 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5

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5 x^{2} - 4 x - 6 = 0

x = \frac{2 + 34}{5}, x = \frac{2 - 34}{5}

Decimal Notation

x = 1.56619 \dots, x = - 0.76619 \dots

Solution steps

5 x^{2} - 4 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 6) = 234

x_{1, 2} = \frac{- ( - 4 ) \pm 2 34}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 34}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 2 34}{2 \cdot 5}

x = \frac{- ( - 4 ) + 2 34}{2 \cdot 5} : \frac{2 + 34}{5}

x = \frac{- ( - 4 ) - 2 34}{2 \cdot 5} : \frac{2 - 34}{5}

The solutions to the quadratic equation are:

x = \frac{2 + 34}{5}, x = \frac{2 - 34}{5}

6 x^{2} - 16 x

\frac{x}{9} = 3

x^{2} - 14 = 2

∣ 2 x - 1 ∣ < 9

8 x^{3} - y^{3}

What are the solutions to the equation 5x^2-4x-6=0 ?
The solutions to the equation 5x^2-4x-6=0 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5
Find the zeros of 5x^2-4x-6=0
The zeros of 5x^2-4x-6=0 are x=(2+sqrt(34))/5 ,x=(2-sqrt(34))/5