What is the answer to 7x-2(x-3)=5(x+1)+3(7-4x) ?

The answer to 7x-2(x-3)=5(x+1)+3(7-4x) is x= 5/3

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7x-2(x-3)=5(x+1)+3(7-4x)

7 x - 2 (x - 3) = 5 (x + 1) + 3 (7 - 4 x)

x = \frac{5}{3}

Decimal Notation

x = 1.66666 \dots

Solution steps

7 x - 2 (x - 3) = 5 (x + 1) + 3 (7 - 4 x)

Expand

- 2 (x - 3) : - 2 x + 6

7 x - 2 x + 6 = 5 (x + 1) + 3 (7 - 4 x)

Add similar elements:

7 x - 2 x = 5 x

5 x + 6 = 5 (x + 1) + 3 (7 - 4 x)

Expand

5 (x + 1) + 3 (7 - 4 x) : - 7 x + 26

5 x + 6 = - 7 x + 26

Move

6

to the right side

5 x = - 7 x + 20

Move

7 x

to the left side

12 x = 20

Divide both sides by

12

x = \frac{5}{3}

x, y = ∣ f ∣

5 = \frac{1}{4} x + 2

x, y = 2 x y

\frac{x}{2} + 6 = 3 - x

4 \frac{1}{6} - 1 \frac{1}{3} x = 4 x + 3 \frac{5}{18}

What is the answer to 7x-2(x-3)=5(x+1)+3(7-4x) ?
The answer to 7x-2(x-3)=5(x+1)+3(7-4x) is x= 5/3
Solve for x: 7x-2(x-3)=5(x+1)+3(7-4x)
The solution is x= 5/3