What is the answer to log_{10}(3)(1-x)=-2 ?

The answer to log_{10}(3)(1-x)=-2 is x=(2+log_{10}(3))/(log_{10)(3)}

Solve for x: log_{10}(3)(1-x)=-2

The solution is x=(2+log_{10}(3))/(log_{10)(3)}

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lo g_{10} (3) (1 - x) = - 2

x = \frac{2 + lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

Decimal Notation

x = 5.19180 \dots

Solution steps

lo g_{10} (3) (1 - x) = - 2

Divide both sides by

lo g_{10} (3)

1 - x = - \frac{2}{lo g _{10} ( 3 )}

Move

1

to the right side

- x = - \frac{2}{lo g _{10} ( 3 )} - 1

Divide both sides by

- 1

x = \frac{2 + lo g _{10} ( 3 )}{lo g _{10} ( 3 )}

\frac{1}{2} + \frac{3}{4} - A = - 3

\frac{x}{9} \cdot 15 - 47 = 28

a, 25 = 20 a + 15 b + 25 c

75 + 60 + 9 + 3 x = 180

(4 x + 6) - 2 x = (x - 6) + 10 + 14

What is the answer to log_{10}(3)(1-x)=-2 ?
The answer to log_{10}(3)(1-x)=-2 is x=(2+log_{10}(3))/(log_{10)(3)}
Solve for x: log_{10}(3)(1-x)=-2
The solution is x=(2+log_{10}(3))/(log_{10)(3)}