What is the answer to (5x+1)/5+(3x-2)/3+(2x-3)/2 =0 ?

The answer to (5x+1)/5+(3x-2)/3+(2x-3)/2 =0 is x= 59/90

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(5x+1)/5+(3x-2)/3+(2x-3)/2 =0

\frac{5 x + 1}{5} + \frac{3 x - 2}{3} + \frac{2 x - 3}{2} = 0

x = \frac{59}{90}

Decimal Notation

x = 0.65555 \dots

Solution steps

\frac{5 x + 1}{5} + \frac{3 x - 2}{3} + \frac{2 x - 3}{2} = 0

Multiply by LCM

6 (5 x + 1) + 10 (3 x - 2) + 15 (2 x - 3) = 0

Expand

6 (5 x + 1) + 10 (3 x - 2) + 15 (2 x - 3) : 90 x - 59

90 x - 59 = 0

Move

59

to the right side

90 x = 59

Divide both sides by

90

x = \frac{59}{90}

x, g = f + 2

x + 14 = 20

8 x + 16.2 = 1.6

\frac{x - a - b}{c} + \frac{x - b - c}{a} + \frac{x - c - a}{b} = 3

\frac{2 x + 2}{3} = 1

What is the answer to (5x+1)/5+(3x-2)/3+(2x-3)/2 =0 ?
The answer to (5x+1)/5+(3x-2)/3+(2x-3)/2 =0 is x= 59/90
Solve for x: (5x+1)/5+(3x-2)/3+(2x-3)/2 =0
The solution is x= 59/90