What is the answer to (2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)] ?

The answer to (2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)] is x=-32/3

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(2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)]

\frac{2 x + 1}{5} - \frac{x + 1}{3} = 2 [\frac{3 x}{10} - (\frac{x}{6} - 1)]

x = - \frac{32}{3}

Decimal Notation

x = - 10.66666 \dots

Solution steps

\frac{2 x + 1}{5} - \frac{x + 1}{3} = 2 [\frac{3 x}{10} - (\frac{x}{6} - 1)]

Expand

\frac{2 x + 1}{5} - \frac{x + 1}{3} : \frac{x}{15} - \frac{2}{15}

Expand

2 (\frac{3 x}{10} - (\frac{x}{6} - 1)) : \frac{4 x}{15} + 2

\frac{x}{15} - \frac{2}{15} = \frac{4 x}{15} + 2

Multiply both sides by

15

x - 2 = 4 x + 30

Move

2

to the right side

x = 4 x + 32

Move

4 x

to the left side

- 3 x = 32

Divide both sides by

- 3

x = - \frac{32}{3}

y, (D^{2} - 4) (D + 2) y = 0

t, \frac{d S}{d t} = a \cdot v

x + 4 = 3 (x - 4)

x, ln (y) = x - 2

\frac{b}{7 - 12} = 8

What is the answer to (2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)] ?
The answer to (2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)] is x=-32/3
Solve for x: (2x+1)/5-(x+1)/3 =2[(3x)/(10)-(x/6-1)]
The solution is x=-32/3