What is the answer to solvefor a,(a+b/c)(d-e)=f ?

The answer to solvefor a,(a+b/c)(d-e)=f is a= f/(d-e)-b/c ;\quad d\ne e

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solvefor a,(a+b/c)(d-e)=f

solve for

a, (a + \frac{b}{c}) (d - e) = f

a = \frac{f}{d - e} - \frac{b}{c}; d \neq = e

Solution steps

(a + \frac{b}{c}) (d - e) = f

Divide both sides by

d - e; d \neq = e

a + \frac{b}{c} = \frac{f}{d - e}; d \neq = e

Move

\frac{b}{c}

to the right side

a = \frac{f}{d - e} - \frac{b}{c}; d \neq = e

x, \frac{x + 1}{3} - \frac{y - 1}{6} = - 1

\frac{y - 6}{4} = \frac{y}{7}

(x - 5) 2 - 9 = 0

12 (x - a) (x - b) = 12 x^{2} - 7 x - 12

7 x - 2 [3 - 4 (x + 7) + 5 x] - 8 = 17 (x - 1)

What is the answer to solvefor a,(a+b/c)(d-e)=f ?
The answer to solvefor a,(a+b/c)(d-e)=f is a= f/(d-e)-b/c ;\quad d\ne e